If the transmitted beam is one-half of the initial intensity after shielding, how many HVLs of thickness were used?

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Multiple Choice

If the transmitted beam is one-half of the initial intensity after shielding, how many HVLs of thickness were used?

Explanation:
HVLs represent the thickness needed to cut the beam’s intensity in half. After passing through n HVLs, the remaining intensity is I = I0 × (1/2)^n. If the transmitted intensity is half of the original, then (1/2)^n = 1/2, which gives n = 1. So one HVL is the thickness that reduces the beam to 50% of its initial value. For context, two HVLs would reduce to 25%, and a half HVL would leave about 70.7%.

HVLs represent the thickness needed to cut the beam’s intensity in half. After passing through n HVLs, the remaining intensity is I = I0 × (1/2)^n. If the transmitted intensity is half of the original, then (1/2)^n = 1/2, which gives n = 1. So one HVL is the thickness that reduces the beam to 50% of its initial value. For context, two HVLs would reduce to 25%, and a half HVL would leave about 70.7%.

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