If dose rate at 1 m is 800 mSv/h, what is the dose rate at 2 m according to the inverse square law?

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Multiple Choice

If dose rate at 1 m is 800 mSv/h, what is the dose rate at 2 m according to the inverse square law?

Explanation:
The dose rate follows the inverse square law: doubling the distance from the source reduces the dose rate by a factor of four. Starting at 1 m with 800 mSv/h, moving to 2 m makes the rate 800 divided by 4, which is 200 mSv/h. So the correct result is 200 mSv/h. This checks out because the dose rate decreases with the square of the distance, not linearly. At 2 m, you’re four times farther away, hence one quarter of the original intensity.

The dose rate follows the inverse square law: doubling the distance from the source reduces the dose rate by a factor of four. Starting at 1 m with 800 mSv/h, moving to 2 m makes the rate 800 divided by 4, which is 200 mSv/h. So the correct result is 200 mSv/h.

This checks out because the dose rate decreases with the square of the distance, not linearly. At 2 m, you’re four times farther away, hence one quarter of the original intensity.

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