How is shielding thickness t calculated from HVL data for a gamma source?

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Study for the Health Physics (PMT 102A) Test. Access multiple-choice questions, explanatory hints, and detailed answers. Enhance your preparation confidently and get ready for the exam!

Multiple Choice

How is shielding thickness t calculated from HVL data for a gamma source?

Explanation:
HVL is the thickness that reduces the gamma-ray intensity by a factor of 2, so the transmitted intensity after shielding is I = I0 × 2^(-t/HVL). Rewriting, I0/I = 2^(t/HVL). Solving for t gives t/HVL = log2(I0/I), hence t = HVL × log2(I0/I). You can also write this with natural logs as t = HVL × ln(I0/I) / ln 2. This is the correct way to extract thickness from HVL data.

HVL is the thickness that reduces the gamma-ray intensity by a factor of 2, so the transmitted intensity after shielding is I = I0 × 2^(-t/HVL). Rewriting, I0/I = 2^(t/HVL). Solving for t gives t/HVL = log2(I0/I), hence t = HVL × log2(I0/I). You can also write this with natural logs as t = HVL × ln(I0/I) / ln 2. This is the correct way to extract thickness from HVL data.

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